d and f BLOCK ELEMENTS MCQ Quiz: GKFix - Bridge of Knowledge

Question 1416

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Why does copper's positive E°(M2+/M) value prevent it from liberating H2 from acids?

Because copper does not form ions.
Because the reaction has a positive cell potential, making it spontaneous.
Because copper is less reactive than hydrogen.
Because the reaction Cu + 2H+ → Cu2+ + H2 would have a negative cell potential, making it non-spontaneous.

Question 1417

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According to the text, which type of acids can react with copper metal?

Only dilute acids.
Any type of acid.
Only non-oxidizing acids.
Only oxidizing acids.

Question 1418

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What is the main reason provided in the text for copper's positive E°(M2+/M) value?

Its low atomization enthalpy is balanced by its high hydration enthalpy.
Its high atomization enthalpy is balanced by its equally high hydration enthalpy.
Its low atomization enthalpy is not balanced by its hydration enthalpy.
Its high atomization enthalpy (ΔaH°) is not sufficiently balanced by its low hydration enthalpy (ΔhydH°).

Question 1419

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Why is the statement 'only the sum of first and second ionization enthalpies determines the E° trend' an oversimplification?

Because ionization enthalpies are always constant.
Because hydration enthalpy is the only important factor.
Because atomization enthalpy is always negligible.
Because it ignores the significant contributions of atomization enthalpy and hydration enthalpy, as well as specific electronic effects.

Question 1420

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If the atomization enthalpy of a metal M were significantly lower, how would this likely affect its E°(M2+/M) value, assuming other factors remain constant?

The E°(M2+/M) value would likely become less negative.
The E°(M2+/M) value would remain unchanged.
The E°(M2+/M) value would become positive.
The E°(M2+/M) value would likely become more negative.

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