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Question #91975
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Question
In Example 14.2, what is the calculated hole concentration in the doped silicon?
A. 1.5 × 10¹⁶ m⁻³
B. 5 × 10²² m⁻³
C. 4.5 × 10⁹ m⁻³
D. 2.25 × 10³² m⁻³
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