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EQUILIBRIUM
Question #29424
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What is the expression for the second ionization constant (Ka2) of a dibasic acid HX–?
A. Ka2 = [H+][X^2–]/[HX–]
B. Ka2 = [H+][HX–]/[H2X]
C. Ka2 = [H+][X^2–]/[H2X]
D. Ka2 = [H+][H2X]/[HX–]
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