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Question
What is the formula for the effective capacitance of three capacitors in series?
A. C' = C1 + C2 + C3
B. C' = (C1×C2×C3)/(C1+C2+C3)
C. 1/C' = 1/C1 + 1/C2 + 1/C3
D. C' = 3C
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