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Question #79177
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Question
What is the effective capacitance of two capacitors C₁ and C₂ in series?
A. C = C₁ + C₂
B. C = (C₁C₂)/(C₁ + C₂)
C. C = 1/(C₁ + C₂)
D. C = (C₁ + C₂)/(C₁C₂)
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