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THERMODYNAMICS
Question #73001
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Question
What is the correct expression for log K in terms of ∆rG⁰?
A. log K = ∆rG⁰ / (2.303 RT)
B. log K = –∆rG⁰ / (2.303 RT)
C. log K = RT / (2.303 ∆rG⁰)
D. log K = –2.303 RT / ∆rG⁰
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