In the half-reaction 6 Fe^2+ -> 6Fe^3+ + 6 e–, what role does Fe^2+ play? - d and f BLOCK ELEMENTS Quiz | GKFix.in

Content protected from screenshots

Question

In the half-reaction 6 Fe^2+ -> 6Fe^3+ + 6 e–, what role does Fe^2+ play?

A. It acts as an oxidizing agent
B. It acts as a reducing agent
C. It is reduced
D. It remains unchanged

Related Questions