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Question #31061
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Question
What quadratic equation is obtained when solving for α in 0.02 M HF with Ka = 3.2 × 10⁻⁴?
A. α² – 0.02α + Ka = 0
B. α² + 1.6 × 10⁻²α – 1.6 × 10⁻² = 0
C. 2α = Ka × c
D. α = √(Ka/c)
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