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EQUILIBRIUM
Question #31054
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What is the correct expression for Ka of HF based on equilibrium concentrations?
A. Ka = [HF]/[H3O+][F–]
B. Ka = [H3O+]^2
C. Ka = [H3O+][F–]/[HF]
D. Ka = [HF][H2O]/[H3O+][F–]
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