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EQUILIBRIUM
Question #27904
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What is the correct equilibrium expression for the reaction: CH3COOH ⇌ CH3COO⁻ + H⁺?
A. K = [CH3COOH] / ([CH3COO⁻][H⁺])
B. K = [CH3COO⁻] / [H⁺]
C. K = [CH3COO⁻][H⁺] / [CH3COOH]
D. K = [CH3COO⁻]² / [CH3COOH]
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